Consider a solution of a weak acid at a pH equal to its pKa.
By how much would the pH change, and in which direction, if we added to this solution enough base to neutralize 10% of the total acid?PH equal to its pKa chemistry question?
pH = pka + log [base]/[acid]
Initially, pH = pka, meaning that [base]:[acid] is 1:1
After neutralizing 10% of the acid,
pH = pka + log 1.1/0.9
pH = pka + 0.87
Therefore, pH increases by 0.087
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