Calculate the pH change when of 1 mL of 0.2 M HCl is added to 50 mL of deionized water.?

Calculate the pH change when of 1 mL of 0.2 M HCl is added to 50 mL of deionized water.

How does this pH value change compare to those obtained when 1 mL of 0.2 M HCl is added

to the buffers?Calculate the pH change when of 1 mL of 0.2 M HCl is added to 50 mL of deionized water.?
mol of H+ added = 1 ml * 0.2 mol / L = 0.2 mmol H+.

[H+] = 0.2 mmol / (51 ml) = 3.92 * 10 ^-3



pH = -log(3.92 * 10 ^-3) = 2.40



pH change = 7.00 - 2.40 = 4.6



if the acid is added to the buffer, it won't make a big change in pH.