For example, say I have a 1/4 cup of lemon juice that has a pH of 2.5. If I add 1/4 cup of water and dilute it by half, how does the pH change? It is half as acidic--something like pH of 4.75? Is there a simple way to calculate this?How does diluting a solution affects its pH?
pH = 2.5 = -Log[H+]
Log[H+] = -2.5 = 0.5 - 3
[H+] = 3.2 x 10^-3 Next dilute by half:
[H+] = 1.6 x 10^-3
Log[H+] = 0.2 - 3 = 2.8
pH = -Log[H+] = -2.8How does diluting a solution affects its pH?
It brings it closer to a ph of 7, which is the neutral ph
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