i need to do second part: by how much will the Ph change if 0.025 mol of HCL is added to 1.00 L of the buffer in problem (i have stated up_What is the PH of a solution that contains 0.15M hc2h3o4 and 0.25 M c2h3o2? use Ka= 1.8 X 10-5?
CH3COO- + H+ %26gt;%26gt; CH3COOH
moles acetate = 0.25 - 0.025 =0.225
[CH3COO-]= 0.225 / 1.00 L= 0.225
Moles acetic acid = 0.15 + 0.025=0.175
[CH3COOH]= 0.175 / 1.00L = 0.175
pKa = 4.7
pH = pKa + log [CH3COO-]/ [CH3COOH]
pH = 4.7 + log 0.225 / 0.175=4.8
about the first question :
pH = 4.7 + log 0.25/ 0.15= 4.9
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