How would I know if voltage of a volcaic battery is affected by pH changes?

Based on the following statement:

';When balanced, the coefficient x in the equation Cu+xNOsubscript';3'; --%26gt; xNO +Cusuperscript';2+'; is equal to 2';....

based on this statement, the voltage of a voltaic battery is a) unaffected by pH changes, b) increases with increasing pH, c) decreases with increasing pH, or d) is negative. Please explain, if possible, so I can answer a variation of this question on a test. Thank you!How would I know if voltage of a volcaic battery is affected by pH changes?
Ah, Dr. D's class I see?



Write out the two half reactions:

Cu -%26gt; (Cu2+) + (2e-)

(4H+) + (3e-) + (NO3-) -%26gt; (NO) + (2H2O)

Right?

So, if you want to combine these, multiply the Cu half reaction by 3 and the NO3- half reaction by 2. The electrons cancel out, and that is why the answer to #16 is B.

Now, the SECOND you see H+ on either side of a half reaction, you know for sure that the reaction is affected by pH. Ok? Just remember that. Also remember that H+ is reactive. As pH goes up, things get more basic- which means less H+ ions. This means less reactivity. Less H+ means less voltage. The answer is C) The voltage decreases with increasing pH!



Good luck on your Midterm! :)