If we add 0.010 mol of solid NaOH to 1.00 liter of a buffer solution that is 0.100 M in CH3COOH and 0.100 M in NaCH3COO, how much will [H3O+] and pH change? Assume that there is no volume change due to the addition of solid NaOH.Can someone please help me with this chemistry problem?
fianl pH = pKa + lg [base]/[acid]
= -lg (Ka) + lg[(0.1+0.01)/(0.1-0.01)]
Subscribe to:
Post Comments
(Atom)
No comments:
Post a Comment