You must know that HCl is a very strong acid, therfore extremely small quantities are required to produce a solution with pH = 6, 5 and 4.
The [H+] at pH 6 = 0.000001M
Commercial HCl is 12.0M
Now if you wish to prepare a 1 litre solution with pH = 6.0, [H+] = 10^-6
M1V1=M2V2
12.0*V1 = 10^-6*1000
V1 = 8.33*10^-5 ml
Similarly, a pH 5.0 solution will require 8.33*10^-4ml, and
pH 4.0 solution will require 8.33*10^-3ml all dissolved to 1000ml solution
I am sure that you can see the impracticability of this, because measuring out these extremely small volumes is difficult.
A more practical method would be to prepare a known dilution of the concentrated HCl for instance a 1.0M solution:
Dissolve 83.33ml of the conc acid in 1 litre of solution . This will give a solution with pH = 0.00
Now you can make a series of solutions with a scale of pH by sucesive 10 fold dilutions.
Dilute the 1M solution 100ml in 1000ml to get pH =1.00
Dilute this solution 100ml in 1000ml solution to get pH = 2.0
Dilute this solution 100ml in 1000ml solution top get pH = 3.0
And so on to get your desired pH 4, 5 and 6. It is not easy because the HCl is a very strong acid.
No comments:
Post a Comment