the answer is 5.4 but im not sure howWhat is the change in ph when 0.025mole of NaOH is added to 1.00Lof pure water?
pH of pure water = 7.00
NaOH is a strong base : NaOH = Na+ + OH-
[OH-]= 0.025 mol / 1.00 L = 0.025 M
pOH = - log 0.025 =1.60
pH = 14 - pOH = 14 - 1.60= 12.4
delta pH = 12.4 - 7.0 =5.4
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