A beaker with 135 mL of an acetic acid buffer with a pH of 5.00 is sitting on a benchtop. The total molarity of acid and conjugate base in this buffer is 0.1 M. A student adds 7.80 mL of a 0.400 M solution to the beaker. How much will the pH change? The pKa of acetic acid is 4.76.A beaker with 135 mL of an acetic acid buffer with a pH of 5.00....Find change in pH?
let x = [CH3COOH]
let y = [CH3COO-]
5.00 = 4.76 + log y/x
5 - 4.76 =0.24
10^0.24 = 1.74 = y/x
1.74 x = y
x + y = 0.1
x + 1.74 x = 0.1
2.74 x = 0.1
x = 0.0365 M
y = 0.1 - 0.0365 =0.0635 M
moles acetic acid = 0.135 L x 0.0365 =0.00493
moles acetate = 0.135 L x 0.0635 = 0.00857
7.90 mL of 0.400 M of ??????
hope helps
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