I already calculated that the pH will be around 4.75 initially.How much acid solution is needed to change the pH by 0.1 pH units?
moles acetic acid = moles acetate = 0.100 L x 1.0 M = 0.100
we need a pH of 4.65
4.75 - 4.65 =0.1
pKa = 4.75
4.65 - 4.75=- 0.1
10^-0.1 =0.79 = [acetate]/ [acetic acid] = 0.100-x/0.100+x
0.079 + 0.79 x = 0.100-x
0.021 = 1.79 x
x = 0.0117 moles of acetic acid neededHow much acid solution is needed to change the pH by 0.1 pH units?
can someone please explain this will a little more detail. I'm not getting where all of these numbers are coming from? Thanks
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